[Freeswitch-users] Socket outbound: How to bridge two calls?

Anthony Minessale anthony.minessale at gmail.com
Thu Nov 6 06:12:17 PST 2008

If that doesn't work one of your uuids are wrong or contains a superfluous
space or some other character
You have to understand that the inbound call that uses "socket" is the same
thing as &park()
They are both in a park state at that point and there is no functional

once both channels are answered and in the park state,
you have 2 choices and they both work, so watch the console log on debug
level to find your mistake.

api uuid_bridge <uuid> <other_uuid>
sendmsg to <uuid> with call-command: execute to execute intercept on

to prove it, just set your script to accept and answer the inbound call then
make the outbound call and do nothing more.
Then at the CLI type:
>console loglevel debug
>show channels

get the 2 uuid from the output
and type:
>uuid_bridge <uuid> <other_uuid>

if this does not work, send me a complete copy of the console output

On Wed, Nov 5, 2008 at 9:05 AM, Dennis <odermann at googlemail.com> wrote:

> hi,
> i am using socket outbound and want to bridge two calls with each other.
> i do the following:
> a call comes in and it gets answered (inbound call). after i send the
> answer to the inbound, i do an originate to &park (outbound).
> after i answered the outbound, i want both sides to be able to talk to
> each other. but when i try uuid_bridge <inbound-uuid> <outbound-uuid>
> it does not work. i do not even get a channel_bridge or something.
> when i do 2 originates and send them to &park(), i can bridge them
> with each other with uuid_bridge.
> what am i doing wrong?
> the other question is, how to unbridge two calls, if they are bridged?
> i can't find anything like an unbridge command.
> thanks
> dennis93
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Anthony Minessale II

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