Hello, I need help using session object, please help me. "Note: While the JavaScript application will continue to execute after a hangup is detected the session object will be gone and any attempt to access it will cause the JavaScript to terminate. Save off any variables you might need for post hangup processing and use your local variables instead." How can i avoid the script termination, is it possible to somehow safely check if the session hungup? exactly i'd like to call an user, if don't answer call another, i can't use simply mod_bridgecall because i know the destinations just in runtime, i try use fetchURLHash to determine the next user, when one fails. var queue = argv; var hash = new Array(); while (true) { // fetch first agent fetchURLHash("http://localhost:8000/lockagent/" + queue + "/"+session.uuid, "hash"); var agent = hash["agent"]; //call agent //... new_session = new Session(session, "sofia/devil/" + agent + "%192.168.1.93", //dest "xml",//dialplan "default",//context "",//cid_name ""), //cid_num "",//network_addr "",//ani "",//anii "",//rdnis "",//username 10);//to // i need help in this condition // on timeout, new_session is done, and if i try access its properties, script terminate if (session.ready() && new_session.ready()) { bridge(session, new_session); fetchURLHash("http://localhost:8000/unlockagent/" + agent + "/" + session.uuid, "hash"); break; } else { // should try again, but script terminated console_log("notice","timeout, try again...\n"); //wait a bit } fetchURLHash("http://localhost:8000/unlockagent/" + agent + "/" + session.uuid, "hash"); } Thanks any help, Tamas