I used channel_name like this <condition field="${Channel_Name}" expression="^FreeTDM/1:1/$"> and that has been working -- freetdm is not working well, but that is another story. Steven Ayre <steveayre@gmail.com> wrote:
Try this:
<extension name="analog test2" continue="true"> <condition field="source" expression="mod_freetdm"> <action application="info"/> </condition> </extension>
That'll dump all the fields and variables set. Are there any that indicate the FXO port? If not, perhaps you need to configure something - check the card's documentation.
If you find there is a variable containing the port, you can check more than one condition. For example: <extension name="analog test2" continue="true"> <condition field="source" expression="mod_freetdm"/> <condition field="${sangoma_fxo_port_variable_name}" expression="^1$"> <action application="set" data="domain_name=$${domain}"/> <action application="set" data="transfer_ringback=$${us-ring}"/> <action application="answer"/> <action application="transfer" data="1000 XML default"/> </condition> </extension>
-Steve
On 1 February 2011 16:17, Eric Michel <eric@bmcrministries.org> wrote:
I've got a Sangoma A200 with six FXO ports and two FXS. I can call out just fine, but I'm having trouble figuring out how to route incoming calls. We've got five POTS lines and all I've been able to do is route all incoming calls to a specific extension. How do I go about routing individual POTS lines to different groups/extensions?
<extension name="analog test2" continue="true"> <condition field="source" expression="mod_freetdm"> <action application="set" data="domain_name=$${domain}"/> <action application="set" data="transfer_ringback=$${us-ring}"/> <action application="answer"/> <action application="transfer" data="1000 XML default"/> </condition> </extension>
That is my current conf/public/inbound dial plan. Shouldn't I be able to add a second condition that tests what FXO port is receiving the call and allow me to route it accordingly? If yes, could I get an example? The answer may be really simple, I've just been unable to find it.
Thanks, Eric
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