[Freeswitch-users] Socket outbound: How to bridge two calls?
birgit at westhawk.co.uk
Wed Nov 5 07:51:15 PST 2008
Is there any reason why your first original and then bridge instead of
bridging your inbound call immediately to the (what will be your)
If that doesn't work, I had to take a channel out of a conference call
and bridge that channel to a new person. I used 'intercept' in the end:
var sSession = new
where sSession is the newly (latest) originated call
and uuid the identifier of the channel in the conference call.
As far as I know, 'unbridge' as command doesn't exist.
I wouldn't know how to achieve that.
Hope the above helps.
On 05/11/08 15:05, Dennis wrote:
> i am using socket outbound and want to bridge two calls with each other.
> i do the following:
> a call comes in and it gets answered (inbound call). after i send the
> answer to the inbound, i do an originate to &park (outbound).
> after i answered the outbound, i want both sides to be able to talk to
> each other. but when i try uuid_bridge <inbound-uuid> <outbound-uuid>
> it does not work. i do not even get a channel_bridge or something.
> when i do 2 originates and send them to &park(), i can bridge them
> with each other with uuid_bridge.
> what am i doing wrong?
> the other question is, how to unbridge two calls, if they are bridged?
> i can't find anything like an unbridge command.
-- Birgit Arkesteijn, birgit at westhawk.co.uk,
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