You lots of options, but this is the more traditional:

1. Use the toll_allow option in the dialplan rules. :

<extension name="isp1">
    <condition field="${toll_allow}" expression="isp1"/>
    <condition field="destination_number" expression="(^\d+$|^or-whatever-your-dialstring-is$)">
      <action application="set" data="effective_caller_id_number=${outbound_caller_id}"/>
      <action application="set" data="effective_caller_id_name=${outbound_caller_id_name}"/>
      <action application="bridge" data="sofia/gateway/isp1/$1"/>
    </condition>
  </extension>

The user will look something like this:

<include>
  <user id="5001">
    <params>
      <param name="password" value="$${default_password}"/>
      <param name="vm-password" value="5001"/>
    </params>
    <variables>
      <variable name="toll_allow" value="isp1"/>
      <variable name="accountcode" value="5001"/>
      <variable name="user_context" value="default"/>
      <variable name="effective_caller_id_name" value="Extension 5001"/>
      <variable name="effective_caller_id_number" value="5001"/>
      <variable name="outbound_caller_id_name" value="$${outbound_caller_name}"/>
      <variable name="outbound_caller_id_number" value="my-fancy-aon-number"/>
      <variable name="callgroup" value="wombat"/>
    </variables>
  </user>
</include>

2. For unique caller ID, change it in the user's account as above ^

3. Alternatively, you can add a condition to check the user's internal caller ID and route based on that:

    <condition field="effective_caller_id_number" expression="^5001$|^5002$">
Francis

On 2014-05-12 16:40, Роман aka iTUX wrote:

Hello!

 

I have several users in freeswitch/directory/default (for example 5001, 5002, 5003). Also have several ISP in freeswitch/sip_profiles (isp0, isp1, isp2, isp3).

 

Default routing define in freeswitch/dialplan/default and  by default used isp0 for outbound calls.

 

How i can organize outbound calls for user 5001 via isp1 and for user 5002 via isp2? Or user 5001 and 5002 via isp1, but with different A-numbers (aon)

 

Thanks for advice

 

--
Kind regards,

 

Roman

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