<br><br><div class="gmail_quote">On Tue, Aug 17, 2010 at 9:19 AM, Nigel Kent <span dir="ltr"><<a href="mailto:ktngl@yahoo.co.uk">ktngl@yahoo.co.uk</a>></span> wrote:<br><blockquote class="gmail_quote" style="margin: 0pt 0pt 0pt 0.8ex; border-left: 1px solid rgb(204, 204, 204); padding-left: 1ex;">
<table border="0" cellpadding="0" cellspacing="0"><tbody><tr><td style="font: inherit;" valign="top">I see, how clumsy of me.<br><br>I have been focusing too much on capturing two #'s. Still is this not possible some way.<br>
<br>I want the two ##'s because it is already the common usage in what I want to do so would prefer to keep the same<br></td></tr></tbody></table></blockquote><div>Well, you can capture everything with a regex of ".*" and then just rely on the timeout. It's the only way to do it without a lot of hassle. If you're into hassle then you have other options:<br>
<br>Capture digits one at a time and do fun/crazy logic to see if you have what you need<br>Hack playandgetdigits to allow ## to be a terminator.<br><br>I'd start with eliminating the terminator characters first and testing it out. You can shorten your timeout value so the user isn't waiting too long after dialing ##. Give it a test drive and see if it will work.<br>
<br>-MC<br></div></div>