[Freeswitch-users] week day and time condition possible bug
Ken Rice
krice at freeswitch.org
Sun Sep 4 20:08:31 MSD 2016
Wrong there is no wrap around time.. There is only ranges of time on a day...
Look back at the code i pasted again.
If start time > end time then we check to see if current time < end time OR > start time again i. Seconds and for symplicity we'll use just 60 of them
If the rand is 45 through 15 then we do the false part of the exp?true:false which is (val >= range_start || val <= range_end)
So now start is 45 and end is 15 so we look for the time to >= 45 or <= 15 again on day 1 or day 2 assuming wday="1-2"
So there is no "wrap around time" there is no wday=1-2" and timeofday="9p-5a" and an expectation of that only working from 9p on day 1 to 9p on day 2 thats day 1 from 00:00 to 05:00 and from 21:00 til 23:59:59 then the same thing on day 2.
Sent from my iPhone
> On Sep 4, 2016, at 10:33 AM, Bipin Patel <bipin at xbipin.com> wrote:
>
> thanks for the detailed explanation :)
>
> so what i make of this is if u use a wrap around time or u want full 24 hours either in same day or across days then u need to set one second lower so "5:00-5:00" should actually be "5:00:00-4:59:59" which would be 5am from today to 4:59:59am tomorrow and same goes for "00:00:00-00:00:00" which should be "00:00:00-23:59:59"
>
> now same if u combine with wday then again u need to specify a second lower in the max time for it to work properly if the start and end time is set same or it will read it as 0
>
>
> Regards,
> Bipin
>
>
> -------- Original Message --------
> Subject: Re: [Freeswitch-users] week day and time condition possible bug
> From: Ken Rice <krice at freeswitch.org>
> To: FreeSWITCH Users Help <freeswitch-users at lists.freeswitch.org>
> Date: 9/4/2016, 7:14:25 PM
>> Ok lets try to make sense of this.
>>
>> The time-of-day matching in your initial email
>> >> <condition wday="1-2" time-of-day="00:00:00-00:00:00" break="never">
>>
>> happens in 2 stages... stage 1) does wday fall in the range of 1-2
>> wday="1-2"
>> wdaymin = 1
>> wdayamx = 2
>> so does if (today >= wday-min || today <= wday-max).... if you set this for 0-0 or 1-1 then only day 0 or only day 1 would match. Now the above example is simplified psuedo code just for the sake of explanation...
>>
>> The time-of-day matching works similarly... after the value for the time of day field is parsed the following if statement (actually taken from the code) happens
>>
>> if (range_start <= range_end ? (val >= range_start && val <= range_end) : (val >= range_start || val <= range_end)) { ... }
>>
>> so this allos for the range_end to be a lower value... however the same thing happens does the current time val fall in the range of times... so if you set the start and the end time to 00:00:00 the only time it will match is 00:00:00. lets reduce this for the sake of simplicity from the long date to just seconds of the day... 00:00:00 == second 0 for the day... so
>>
>>
>> range start is <= range_end (in fact its 0) so ... we'll do the true half of the expression?true:false statement there...
>> if (val >= range_start && val <= range_end) where val is the current number of seconds into today...
>>
>> so you have told it that the only range that can match is 0 thru 0 inclusive... how can any other time match...
>>
>> so in your example there are only 2 times that will match 00:00:00 on day 1 and 00:00:00 on day 2...
>>
>> the proper way to include an entire day is 00:00:00-23:59:59 which covers all possible seconds in a range
>
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