[Freeswitch-users] dialplan - expression matching and variable - 2nd try

[Weigel, Stefan]

Hi David,

got it! I forgot about the multiple ‘()’ leading to $1, $2 .. $n. I was always using $1, so in some cases it was empty. Dooh..


Thanks!


Best regards

Stefan

Stefan Weigel
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Von: freeswitch-users-bounces at lists.freeswitch.org [mailto:freeswitch-users-bounces at lists.freeswitch.org] Im Auftrag von David Ponzone
Gesendet: Freitag, 21. Januar 2011 11:57
An: FreeSWITCH Users Help
Betreff: Re: [Freeswitch-users] dialplan - expression matching and variable - 2nd try

Stefan,

I am not sure to understand the difference between your 2 trials.
In both cases, you say $1 is empty, so I am not sure what is working in test 2.
Also, you should tell us what number you call to test (500 or 600).

Finally, if you right a regexp, every () group you define will be used to populate $1, $2, etc...
So in:
^(500)$|^(600)$
$1 will contain 500 if you call 500 and then $2 will be empty
$1 will be empty and $2 will contain 600 if it matches

You should write:
^(500|600)$

David Ponzone  Direction Technique
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Le 21/01/2011 à 11:13, Weigel, Stefan a écrit :


Hi all,

sorry for the first message, I hit the wrong keys an Outlook sent the message…once again:


why is the following not working:


  <condition field="destination_number" expression="^(500)$|^(600)$">
    <action application="set" data="dialed_number=$1"/> <-- $1 is empty

when using the above expression, $1 is empty.

If I do it like this


  <condition field="destination_number" expression="^(5\d\d)$|^(6\d\d)$">
    <action application="set" data="dialed_number=$1"/> <-- $1 is empty

It’s working. I don’t understand why.


Thanks in advance and best regards,

Stefan
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