[Freeswitch-users] problem making internal calls

Jason Garland jgarland at gmail.com
Wed Aug 15 11:46:46 EDT 2007


The SIP profile name is an ip address?

How about changing it to "foo.localdomain"

On 8/15/07, Michael Jerris <mike at jerris.com> wrote:
>
>  Is the phone actually registering to freeswitch?  It appears not.  Also, in
> the directory, is the id 5 in the domain 192.1680.0.4?  You will want to
> look in the log before the call is made to see what happens with the
> register attempt (or lack of) from the phone.
>
>  Mike
>
>
>
>  On 8/15/07 3:40 AM, "Craig Kowald"
> <craig.kowald at cubemicrosystems.com> wrote:
>
>
> I am trying to call from one internal phone to another internal phone - but
> I can not get it working :(.
>
>  I have an analog phone connected to a Digium TDM400P and an IP phone
> (identified as user:5)
>
>  In directory.xml I have identified the IP phone as:
>  <user id="5">
>   <params>
>    <param name="password" value="5"/>
>   </params>
>  </user>
>
>
>  In my dialplan I have:
>  <extension name="Internal-5">
>   <condition field="destination_number" expression="^5$">
>    <action application="bridge"
> data="sofia/${sip_profile}/5%${sip_profile}"/>
>   </condition>
>  </extension>
>
>
>  In sophia.xml I try to make it so that sip phones have to register by
> having:
>  <!--<param name="accept-blind-reg" value="true"/> -->
>  <param name="auth-calls" value="true"/>
>  <param name="auth-all-packets" value="true"/>
>
>
>
>  When I dial '5' on the analog phone I can see that freeswitch tries to make
> the connection, but can not:
>
>  [NOTICE] switch_core_state_machine.c:134
> switch_core_standard_on_execute() Execute
> bridge(sofia/${sip_profile}/5%${sip_profile})
>  [DEBUG] switch_core_state_machine.c:158
> switch_core_standard_on_execute() Expanded String
> bridge(sofia/192.168.0.4/5%192.168.0.4)
>  [WARNING] mod_sofia.c:1397 sofia_outgoing_channel() Cannot locate
> registered user 5 at 192.168.0.4
>
>
>  Any ideas/suggestions on how to call internal sip phones ?
>
>
>  Regards,
>  Craig.
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